INGOT CONSISTING OF ALLOY OF HIGH MELTING POINT ACTIVE METAL AND MANUFACTURING METHOD THEREFOR

PROBLEM TO BE SOLVED: To provide an ingot consisting of alloy of a high melting point active metal less in deviation of alloy contents, and a manufacturing method therefor.SOLUTION: A maximum value θ with sharp angle by growth direction of columnar crystal structure CO formed outer side of the cente...

Full description

Saved in:
Bibliographic Details
Main Authors NAKAOKA TAKEHIRO, KANEHASHI HIDEKATSU, KUROSAWA EISUKE
Format Patent
LanguageEnglish
Japanese
Published 29.11.2018
Subjects
Online AccessGet full text

Cover

Loading…
More Information
Summary:PROBLEM TO BE SOLVED: To provide an ingot consisting of alloy of a high melting point active metal less in deviation of alloy contents, and a manufacturing method therefor.SOLUTION: A maximum value θ with sharp angle by growth direction of columnar crystal structure CO formed outer side of the center of an ingot 16 and inside of the ingot, and a central axis O of the ingot 16 is threshold θsatisfying following formulae (1) to (4) or less, wherein permissible value of segregation degree of an alloy element in a radial direction of the ingot 16 is γ[%], equilibration partition coefficient of the alloy element to a high melting point active metal is k[-], material constant of the alloy element is α [sec./m], casting speed of the ingot 16 is V[m/sec.], dissolution rate of a raw material is M [kg/sec.], density of alloy of the high melting point active metal is ρ [kg/m], cross section area of the ingot 16 is A [m], diameter of the ingot 16 is d [m]. γ=abs(1-β)×100 [%] Formula (1), β={k+(1-k)exp(-αV)}/{k+(1-k)exp(-αVcosθ)} Formula (2), V=M/ρA Formula (3), A=πd/4 Formula (4).SELECTED DRAWING: Figure 6 【課題】合金成分の偏りが少ない高融点活性金属の合金からなる鋳塊、および、その製造方法を提供する。【解決手段】鋳塊16の半径方向における合金元素の偏析度の許容値をγcr[%]、高融点活性金属に対する合金元素の平衡分配係数をk0[−]、合金元素の材料定数をα[秒/m]、鋳塊16の鋳造速度をVc[m/秒]、原料の溶解速度をM[kg/秒]、高融点活性金属の合金の密度をρ[kg/m3]、鋳塊16の断面積をA[m2]、鋳塊16の直径をd[m]とすると、鋳塊16の内部であって、前記鋳塊の中央よりも外側に形成された柱状晶組織COの成長方向と、鋳塊16の中心軸Oとがなす鋭角の最大値θが、以下の式(1)〜(4)を満たす閾値θcr以下にされている。γcr=abs(1−βcr)×100[%] ・・・式(1)、βcr={k0+(1−k0)exp(−αVc)}/{k0+(1−k0)exp(−αVccosθcr)} ・・・式(2)、Vc=M/ρA ・・・式(3)、A=πd2/4 ・・・式(4)【選択図】図6
Bibliography:Application Number: JP20180004901