MEASUREMENT DEVICE AND INTERPOLATION PROCESSING PROGRAM

• Main Author: YONEDA YUKI
• Format: Patent
• Language: English; Japanese
• Published: 05.01.2017
• Subjects: ARRANGEMENTS FOR MEASURING TWO OR MORE VARIABLES NOT COVEREDIN A SINGLE OTHER SUBCLASS; MEASURING; MEASURING ELECTRIC VARIABLES; MEASURING MAGNETIC VARIABLES; MEASURING NOT SPECIALLY ADAPTED FOR A SPECIFIC VARIABLE; MEASURING OR TESTING NOT OTHERWISE PROVIDED FOR; PHYSICS; TARIFF METERING APPARATUS; TESTING

PROBLEM TO BE SOLVED: To linearly interpolate necessary values without performing a divide process.SOLUTION: A measurement device of the present invention executes a first process for specifying values Vn, Vm that correspond to a processing object point when deriving a value V10a (V10b) at a processing object point between an L'th reference point and a (L+1)'th reference point, a second process for calculating a value V6 that is a difference between a value V4 at the L'th reference point and a value V5 at the processing object point, a third process for calculating a value V3a that is a difference between a value V1 at the L'th reference point and a value V2 at the (L+1)'th reference point, a fourth process for calculating a value V8 by multiplying the values V3a, V6, and Vm, and a fifth process for shifting the value V8 n bits to the right and converting it to a value V9, adds the value V9 to the value V1 when the value V2 at the (L+1)'th reference point is larger than the value V1 at the L'th reference point to derive a value V10a, and subtracts the value V9 from the value V1 when the value V1 at the L'th reference point is larger than the value V2 at the (L+1)'th reference point to derive a value V10b.SELECTED DRAWING: Figure 2 【課題】除算処理を行わずに必要な値を線形補間する。【解決手段】Ｌ番目の基準点と（Ｌ＋１）番目の基準点との間の処理対象点における値Ｖ１０ａ（Ｖ１０ｂ）の導出時に、処理対象点に対応する値Ｖｎ，Ｖｍを特定する第１の処理、Ｌ番目の基準点における値Ｖ４と処理対象点における値Ｖ５との差である値Ｖ６を演算する第２の処理、Ｌ番目の基準点における値Ｖ１と（Ｌ＋１）番目の基準点における値Ｖ２との差である値Ｖ３ａを演算する第３の処理、値Ｖ３ａ，Ｖ６，Ｖｍを乗じて値Ｖ８を演算する第４の処理、値Ｖ８をｎビット右シフトして値Ｖ９に変換する第５の処理を実行し、Ｌ番目の基準点における値Ｖ１よりも（Ｌ＋１）番目の基準点における値Ｖ２が大きいときに値Ｖ１に値Ｖ９を加算して値Ｖ１０ａを導出し、Ｌ番目の基準点における値Ｖ１が（Ｌ＋１）番目の基準点における値Ｖ２よりも大きいときに値Ｖ１から値Ｖ９を減算して値Ｖ１０ｂを導出する。【選択図】図２