STAINLESS STEEL FOR OIL WELLS AND STAINLESS STEEL PIPE FOR OIL WELLS

A stainless steel for oil wells which has excellent high-temperature corrosion resistance and can stably obtain a strength of not less than 758 MPa is provided. The stainless steel for oil wells contains, by mass%, C: not more than 0.05%, Si: not more than 1.0%, Mn: 0.01 to 1.0%, P: not more than 0....

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Main Authors TOMIO, YUSAKU, AMAYA, HISASHI, OTOME, YOHEI, OMURA, TOMOHIKO, TAKABE, HIDEKI, SEO, MASANAO, KONDO, KUNIO, NAKATSUKA, SHINJIRO, OHE, TARO
Format Patent
LanguageEnglish
French
Published 15.11.2016
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Summary:A stainless steel for oil wells which has excellent high-temperature corrosion resistance and can stably obtain a strength of not less than 758 MPa is provided. The stainless steel for oil wells contains, by mass%, C: not more than 0.05%, Si: not more than 1.0%, Mn: 0.01 to 1.0%, P: not more than 0.05%, S: less than 0.002%, Cr: 16 to 18%, Mo: 1.8 to 3%, Cu: 1.0 to 3.5%, Ni: 3.0 to 5.5%, Co: 0.01 to 1.0%, Al: 0.001 to 0.1%, O: not more than 0.05%, and N: not more than 0.05%, the balance being Fe and impurities, and satisfies Formulas (1) and (2): Cr + 4Ni + 3Mo + 2Cu >= 44 (1) Cr + 3Ni + 4Mo + 2Cu/3 <= 46 (2) where each symbol of element in Formulas (1) and (2) is substituted by the content (mass%) of a corresponding element. L'invention concerne un acier inoxydable pour des puits de pétrole, qui a une excellente résistance à la corrosion à des températures élevées et est apte à atteindre de façon stable une résistance de 758 MPa ou plus. Cet acier inoxydable pour puits de pétrole contient, en % en masse, 0,05 % ou moins de C, moins de 1,0 % de Si, 0,01-1,0 % de Mn, 0,05 % ou moins de P, 0,002 % ou moins de S, 16-18 % de Cr, 1,8-3 % de Mo, 1,0-3,5 % de Cu, 3,0-5,5 % de Ni, 0,01-1,0 % de Co, 0,001-0,1 % d'Al, 0,05 % ou moins de O et 0,05 % ou moins de N, le reste étant constitué de Fe et des impuretés. Cet acier inoxydable pour puits de pétrole satisfait la formule (1) et la formule (2) suivantes. Cr + 4Ni + 3Mo + 2Cu = 44 (1) Cr + 3Ni + 4Mo + 2Cu/3 = 46 (2) A cet égard, on affecte aux teneurs (% en masse) des éléments correspondants les symboles respectifs des éléments de la formule (1) et la formule (2).
Bibliography:Application Number: CA20132863187