On the circular chromatic number of a subgraph of the Kneser graph
Let $n,k,r$ be positive integers with $n \geq rk$ and $r \geq 2$. Consider a circle $C$ with~$n$ points~$1,\ldots,n$ in clockwise order. The $r$-stable \emph{interlacing graph} $\text{IG}_{n,k}^{(r)}$ is the graph with vertices corresponding to $k$-subsets $S$ of $\{1,...,n\}$ such that any two dist...
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Main Authors | , , , |
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Format | Journal Article |
Language | English |
Published |
12.03.2018
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Subjects | |
Online Access | Get full text |
DOI | 10.48550/arxiv.1803.04342 |
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Summary: | Let $n,k,r$ be positive integers with $n \geq rk$ and $r \geq 2$. Consider a
circle $C$ with~$n$ points~$1,\ldots,n$ in clockwise order. The $r$-stable
\emph{interlacing graph} $\text{IG}_{n,k}^{(r)}$ is the graph with vertices
corresponding to $k$-subsets $S$ of $\{1,...,n\}$ such that any two distinct
points in~$S$ have distance at least~$r$ around the circle, and edges
between~$k$-subsets $P$ and $Q$ if they \emph{interlace}: after removing the
points in~$P$ from $C$, the points in~$Q$ are in different connected
components. In this paper we prove that the circular chromatic number of
$\text{IG}_{n,k}^{(r)}$ is equal to $ n/k $ (hence the chromatic number is
$\lceil n/k \rceil$) and that its circular clique number is also $ n/k $.
Furthermore, we show that its independence number is $\binom{n-(r-1)k-1}{k-1}$,
thereby strengthening a result by Talbot. |
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DOI: | 10.48550/arxiv.1803.04342 |