Asymptotic Location of the Zeros of the Faber Polynomials
Let $E$ be a compact set of the complex plane containing more than one point whose complement in the extended complex plane is simply connected. Let $\omega = \phi(z)$ map conformally Ext($E$) into $\vert\omega\vert>1$ and with $\phi(\infty)=\infty.$ The map $\phi(z)$ has the form $$\phi(z)=\frac...
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Published in | Sarajevo journal of mathematics Vol. 1; no. 2; pp. 175 - 184 |
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Main Authors | , |
Format | Journal Article |
Language | English |
Published |
12.06.2024
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Online Access | Get full text |
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Summary: | Let $E$ be a compact set of the complex plane containing more than one point whose complement in the extended complex plane is simply connected. Let $\omega = \phi(z)$ map conformally Ext($E$) into $\vert\omega\vert>1$ and with $\phi(\infty)=\infty.$ The map $\phi(z)$ has the form $$\phi(z)=\frac{z}{c}+a_0+\frac{a_{-1}}{ z} +\frac{a_{-2}}{z^2}+ \cdots$$
The Faber polynomials for $E$, $\phi_n(z)$, consist of the polynomial part of $\phi(z)^n.$
For $\epsilon>0$ given let $$E_\epsilon:=\bigcup_{z\inE}B(z,\epsilon),$$ where $B(z,\epsilon)$ denotes the disk of center $z$ and radius $\epsilon,$ and let $$B_\epsilon:=\mathrm{Br}(E_\epsilon).$$
Let$$\alpha:=\inf_{z\in\mathrm{Br}(E)}~\left\{\theta;~\pi\theta\text{is the exterior angle of $E$ at }z\right\}.$$ A typical result obtained in this work is the Theorem 3.2.
2000 Mathematics Subject Classification. 31E10, 41A10, 41A29, 41A40 |
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ISSN: | 1840-0655 2233-1964 |
DOI: | 10.5644/SJM.01.2.04 |