The competition number of the complement of a cycle

In this paper, we compute the competition number of the complement of a cycle. It is well-known that the competition number of a cycle of length at least 4 is two while the competition number of a cycle of length 3 is one. Characterizing a graph by its competition number has been one of important re...

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Bibliographic Details
Published inDiscrete Applied Mathematics Vol. 161; no. 12; pp. 1755 - 1760
Main Authors Kim, Suh-Ryung, Park, Boram, Sano, Yoshio
Format Journal Article
LanguageEnglish
Published Elsevier B.V 01.08.2013
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Summary:In this paper, we compute the competition number of the complement of a cycle. It is well-known that the competition number of a cycle of length at least 4 is two while the competition number of a cycle of length 3 is one. Characterizing a graph by its competition number has been one of important research problems in the study of competition graphs, and competition numbers of various interesting families of graphs have been found. We thought that it is worthy of computing the competition number of the complement of a cycle. In the meantime, the observation that the complement of an odd cycle of length at least 5 is isomorphic to a circulant graph led us to compute the competition number of a large family of circulant graphs. In fact, those circulant graphs satisfy the long lasting Opsut’s conjecture stating that the competition number of a locally cobipartite graph is at most two.
Bibliography:ObjectType-Article-2
SourceType-Scholarly Journals-1
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content type line 23
ISSN:0166-218X
1872-6771
DOI:10.1016/j.dam.2011.10.034