Mirror symmetry breaking in He isotopes and their mirror nuclei
We study the mirror symmetry breaking of $^6$ He– $^6$ Be and $^8$ He– $^8$ C using the $^4\hbox {He} + XN (X = 2, 4)$ cluster model. The many-body resonances are treated for the correct boundary condition using the complex scaling method. We find that the ground state radius of $^8$ C is larger tha...
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Published in | Progress of theoretical and experimental physics Vol. 2014; no. 8; p. 83 |
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Main Authors | , |
Format | Journal Article |
Language | English |
Published |
Oxford University Press
07.08.2014
|
Subjects | |
Online Access | Get full text |
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Summary: | We study the mirror symmetry breaking of
$^6$
He–
$^6$
Be and
$^8$
He–
$^8$
C using the
$^4\hbox {He} + XN (X = 2, 4)$
cluster model. The many-body resonances are treated for the correct boundary condition using the complex scaling method. We find that the ground state radius of
$^8$
C is larger than that of
$^8$
He due to the Coulomb repulsion in
$^8$
C. On the other hand, the
$0^+_2$
resonances of the two nuclei exhibit the inverse relation; the
$^8$
C radius is smaller than the
$^8$
He radius. This is due to the Coulomb barrier of the valence protons around the
$^4$
He cluster core in
$^8$
C, which breaks the mirror symmetry of the radius in the two nuclei. A similar variation in the radius is obtained in the mirror nuclei,
$^6$
He and
$^6$
Be. A very large spatial extension of valence nucleons is observed in the
$0^+_2$
states of
$^8$
He and
$^8$
C. This property is related to the dominance of the
$(p_{3/2})^2(p_{1/2})^2$
configuration for four valence nucleons, which is understood from the reduction in the strength of the couplings to other configurations by involving the spatially extended components of valence nucleons. |
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ISSN: | 2050-3911 2050-3911 |
DOI: | 10.1093/ptep/ptu112 |