Property (h) of Banach Lattice and Order-to-Norm Continuous Operators

In this paper, we introduce the property (h) on Banach lattices and present its characterization in terms of disjoint sequences. Then, an example is given to show that an order-to-norm continuous operator may not be σ-order continuous. Suppose T:E→F is an order-bounded operator from Dedekind σ-compl...

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Bibliographic Details
Published inMathematics (Basel) Vol. 11; no. 12; p. 2747
Main Authors Zhang, Fu, Shen, Hanhan, Chen, Zili
Format Journal Article
LanguageEnglish
Published Basel MDPI AG 01.06.2023
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Summary:In this paper, we introduce the property (h) on Banach lattices and present its characterization in terms of disjoint sequences. Then, an example is given to show that an order-to-norm continuous operator may not be σ-order continuous. Suppose T:E→F is an order-bounded operator from Dedekind σ-complete Banach lattice E into Dedekind complete Banach lattice F. We prove that T is σ-order-to-norm continuous if and only if T is both order weakly compact and σ-order continuous. In addition, if E can be represented as an ideal of L0(μ), where (Ω,Σ,μ) is a σ-finite measure space, then T is σ-order-to-norm continuous if and only if T is order-to-norm continuous. As applications, we extend Wickstead’s results on the order continuity of norms on E and E′.
ISSN:2227-7390
2227-7390
DOI:10.3390/math11122747