A family of equivalent norms for Lebesgue spaces
If ψ : [ 0 , ℓ ] → [ 0 , ∞ [ is absolutely continuous, nondecreasing, and such that ψ ( ℓ ) > ψ ( 0 ) , ψ ( t ) > 0 for t > 0 , then for f ∈ L 1 ( 0 , ℓ ) , we have ‖ f ‖ 1 , ψ , ( 0 , ℓ ) : = ∫ 0 ℓ ψ ′ ( t ) ψ ( t ) 2 ∫ 0 t f ∗ ( s ) ψ ( s ) d s d t ≈ ∫ 0 ℓ | f ( x ) | d x = : ‖ f ‖ L 1 (...
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Published in | Archiv der Mathematik Vol. 116; no. 2; pp. 179 - 192 |
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Main Authors | , |
Format | Journal Article |
Language | English |
Published |
Cham
Springer International Publishing
01.02.2021
Springer Nature B.V |
Subjects | |
Online Access | Get full text |
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Summary: | If
ψ
:
[
0
,
ℓ
]
→
[
0
,
∞
[
is absolutely continuous, nondecreasing, and such that
ψ
(
ℓ
)
>
ψ
(
0
)
,
ψ
(
t
)
>
0
for
t
>
0
, then for
f
∈
L
1
(
0
,
ℓ
)
, we have
‖
f
‖
1
,
ψ
,
(
0
,
ℓ
)
:
=
∫
0
ℓ
ψ
′
(
t
)
ψ
(
t
)
2
∫
0
t
f
∗
(
s
)
ψ
(
s
)
d
s
d
t
≈
∫
0
ℓ
|
f
(
x
)
|
d
x
=
:
‖
f
‖
L
1
(
0
,
ℓ
)
,
(
∗
)
where the constant in
≳
depends on
ψ
and
ℓ
. Here by
f
∗
we denote the decreasing rearrangement of
f
. When applied with
f
replaced by
|
f
|
p
,
1
<
p
<
∞
, there exist functions
ψ
so that the inequality
‖
|
f
|
p
‖
1
,
ψ
,
(
0
,
ℓ
)
≤
‖
|
f
|
p
‖
L
1
(
0
,
ℓ
)
is not rougher than the classical one-dimensional integral Hardy inequality over bounded intervals
(
0
,
ℓ
)
. We make an analysis on the validity of
(
∗
)
under much weaker assumptions on the regularity of
ψ
, and we get a version of Hardy’s inequality which generalizes and/or improves existing results. |
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ISSN: | 0003-889X 1420-8938 |
DOI: | 10.1007/s00013-020-01534-4 |