Effectiveness of Walker's cancellation theorem

Walker's cancellation theorem for abelian groups tells us that if A$A$ is finitely generated and G$G$ and H$H$ are such that A⊕G≅A⊕H$A \oplus G \cong A \oplus H$, then G≅H$G \cong H$. Deveau showed that the theorem can be effectivized, but not uniformly. In this paper, we expand on Deveau'...

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Bibliographic Details
Published inMathematical logic quarterly Vol. 70; no. 3; pp. 347 - 355
Main Authors Al‐Hellawi, Layth, Alvir, Rachael, Csima, Barbara F., Xie, Xinyue
Format Journal Article
LanguageEnglish
Published Berlin Wiley Subscription Services, Inc 01.08.2024
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Summary:Walker's cancellation theorem for abelian groups tells us that if A$A$ is finitely generated and G$G$ and H$H$ are such that A⊕G≅A⊕H$A \oplus G \cong A \oplus H$, then G≅H$G \cong H$. Deveau showed that the theorem can be effectivized, but not uniformly. In this paper, we expand on Deveau's initial analysis to show that the complexity of uniformly outputting an index of an isomorphism between G$G$ and H$H$, given indices for A$A$, G$G$, H$H$, the isomorphism between A⊕G$A \oplus G$ and A⊕H$A \oplus H$, and the rank of A$A$, is 0′$\mathbf {0^{\prime }}$. Moreover, we find that the complexity remains 0′$\mathbf {0^{\prime }}$ even if the generators in the copies of A$A$ are specified.
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ISSN:0942-5616
1521-3870
DOI:10.1002/malq.202400030