Maximal subgroups of finite groups avoiding the elements of a generating set
We give an elementary proof of the following remark: if G is a finite group and { g 1 , … , g d } is a generating set of G of smallest cardinality, then there exists a maximal subgroup M of G such that M ∩ { g 1 , … , g d } = ∅ . This result leads us to investigate the freedom that one has in the ch...
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Published in | Monatshefte für Mathematik Vol. 185; no. 3; pp. 455 - 472 |
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Main Authors | , |
Format | Journal Article |
Language | English |
Published |
Vienna
Springer Vienna
01.03.2018
Springer Nature B.V |
Subjects | |
Online Access | Get full text |
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Summary: | We give an elementary proof of the following remark: if
G
is a finite group and
{
g
1
,
…
,
g
d
}
is a generating set of
G
of smallest cardinality, then there exists a maximal subgroup
M
of
G
such that
M
∩
{
g
1
,
…
,
g
d
}
=
∅
.
This result leads us to investigate the freedom that one has in the choice of the maximal subgroup
M
of
G
. We obtain information in this direction in the case when
G
is soluble, describing for example the structure of
G
when there is a unique choice for
M
. When
G
is a primitive permutation group one can ask whether is it possible to choose in the role of
M
a point-stabilizer. We give a positive answer when
G
is a 3-generated primitive permutation group but we leave open the following question: does there exist a (soluble) primitive permutation group
G
=
⟨
g
1
,
…
,
g
d
⟩
with
d
(
G
)
=
d
>
3
and with
⋂
1
≤
i
≤
d
supp
(
g
i
)
=
∅
? We obtain a weaker result in this direction: if
G
=
⟨
g
1
,
…
,
g
d
⟩
with
d
(
G
)
=
d
, then
supp
(
g
i
)
∩
supp
(
g
j
)
≠
∅
for all
i
,
j
∈
{
1
,
…
,
d
}
. |
---|---|
ISSN: | 0026-9255 1436-5081 |
DOI: | 10.1007/s00605-016-0985-y |