Toward Improving the Thermal Stability of Negative Electrode Materials: Differential Scanning Calorimetry and In Situ High-Temperature X‑ray Diffraction/X-ray Absorption Spectroscopy Studies of Li2ZnTi3O8 and Related Compounds

• Published in: ACS applied materials & interfaces Vol. 15; no. 12; pp. 15605 - 15615
• Main Authors: Mukai, Kazuhiko, Uyama, Takeshi, Nonaka, Takamasa
• Format: Journal Article
• Language: English
• Published: American Chemical Society 29.03.2023
• Subjects: Energy, Environmental, and Catalysis Applications; exothermic reaction; spinel; negative electrode; solid electrolyte interphase; thermal runaway; lithium-ion battery
• ISSN: 1944-8244; 1944-8252
• DOI: 10.1021/acsami.3c01123

Negative electrode materials with high thermal stability are a key strategy for improving the safety of lithium-ion batteries for electric vehicles without requiring built-in safety devices. To search for crucial clues into increasing the thermal stability of these materials, we performed differential scanning calorimetry (DSC) and in situ high-temperature (HT)-X-ray diffraction (XRD)/X-ray absorption (XAS) up to 450 °C with respect to a solid-solution compound of Li4/3–2x/3Zn x Ti5/3–x/3O4 with 0 ≤ x ≤ 0.5. The DSC profile of fully discharged x = 0.5 (Li2ZnTi3O8) with a LiPF6-based electrolyte could be divided into three temperature (T) regions: (i) T ≤ 250 °C for ΔH accum i, (ii) 250 °C < T ≤ 350 °C for ΔH accum ii, and (iii) T > 350 °C for ΔH accum iii, where ΔH accum n is the accumulated change in enthalpy in region n. The HT-XRD/XAS analyses clarified that ΔH accum i and ΔH accum ii originated from the decomposition of solid electrolyte interphase (SEI) films and the formation of a LiF phase, respectively. Comparison of the DSC profiles with x = 0 (Li­[Li1/3Ti5/3]­O4) and graphite revealed the operating voltage, i.e., amount of SEI films, and stability of the crystal lattice play significant roles in the thermal stability of negative electrode materials. Indeed, the highest thermal stability was attained at x = 0.25 using this approach.