THERMOELECTRIC CONVERSION MATERIAL AND METHOD OF PRODUCING THE SAME, AND THERMOELECTRIC CONVERSION ELEMENT, THERMOELECTRIC CONVERSION MODULE, AND MOVING BODY
PROBLEM TO BE SOLVED: To provide a thermoelectric conversion material having high thermoelectric conversion characteristics even when used at high temperatures.SOLUTION: A thermoelectric conversion material contains a Si clathrate compound represented by chemical formula: LnAGaAlSi. In the chemical...
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11.10.2018
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Abstract | PROBLEM TO BE SOLVED: To provide a thermoelectric conversion material having high thermoelectric conversion characteristics even when used at high temperatures.SOLUTION: A thermoelectric conversion material contains a Si clathrate compound represented by chemical formula: LnAGaAlSi. In the chemical formula, Ln represents lanthanoid, and A represents Ba or Sr. In the chemical formula, expressions of 0<a≤4, 7.6≤a+b≤8.4, 0≤c≤16, 0≤d≤16, 22<e≤38, and a+b+c+d+e=54 are satisfied, and c and d are not 0 at the same time. The Si clathrate compound has a Si clathrate compound phase, a Si phase, and a lanthanoid-containing phase. When A in the chemical formula is Sr, the proportion α of the Si clathrate compound phase in the Si clathrate compound satisfies 0.35≤α<1, the proportion β of the Si phase satisfies 0<β<0.38, and the proportion γ of the lanthanoid-containing phase satisfies 0<γ<0.65. When A in the chemical formula is Ba, the proportion α satisfies 0.75≤α<1, the proportion β satisfies 0<β<0.14, and the proportion γ satisfies 0<γ<0.25.SELECTED DRAWING: Figure 1
【課題】高温下で使用されても熱電変換特性が高い熱電変換材料を提供する。【解決手段】熱電変換材料は、化学式LnaAbGacAldSieで表されるSiクラスレート化合物を含有する。化学式中のLnはランタノイドを示し、AはBa又はSrを示す。化学式は、数式0<a≦4、7.6≦a+b≦8.4、0≦c≦16、0≦d≦16、22<e≦38、a+b+c+d+e=54を満たし、c及びdは同時に0とはならない。Siクラスレート化合物は、Siクラスレート化合物相、Si相、ランタノイド含有相を有し、化学式中のAがSrである場合は、Siクラスレート化合物中のSiクラスレート化合物相の割合αは0.35≦α<1、Si相の割合βは0<β<0.38、ランタノイド含有相の割合γは0<γ<0.65であり、化学式中のAがBaである場合は、割合αは0.75≦α<1、割合βは0<β<0.14、割合γは0<γ<0.25である。【選択図】図1 |
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AbstractList | PROBLEM TO BE SOLVED: To provide a thermoelectric conversion material having high thermoelectric conversion characteristics even when used at high temperatures.SOLUTION: A thermoelectric conversion material contains a Si clathrate compound represented by chemical formula: LnAGaAlSi. In the chemical formula, Ln represents lanthanoid, and A represents Ba or Sr. In the chemical formula, expressions of 0<a≤4, 7.6≤a+b≤8.4, 0≤c≤16, 0≤d≤16, 22<e≤38, and a+b+c+d+e=54 are satisfied, and c and d are not 0 at the same time. The Si clathrate compound has a Si clathrate compound phase, a Si phase, and a lanthanoid-containing phase. When A in the chemical formula is Sr, the proportion α of the Si clathrate compound phase in the Si clathrate compound satisfies 0.35≤α<1, the proportion β of the Si phase satisfies 0<β<0.38, and the proportion γ of the lanthanoid-containing phase satisfies 0<γ<0.65. When A in the chemical formula is Ba, the proportion α satisfies 0.75≤α<1, the proportion β satisfies 0<β<0.14, and the proportion γ satisfies 0<γ<0.25.SELECTED DRAWING: Figure 1
【課題】高温下で使用されても熱電変換特性が高い熱電変換材料を提供する。【解決手段】熱電変換材料は、化学式LnaAbGacAldSieで表されるSiクラスレート化合物を含有する。化学式中のLnはランタノイドを示し、AはBa又はSrを示す。化学式は、数式0<a≦4、7.6≦a+b≦8.4、0≦c≦16、0≦d≦16、22<e≦38、a+b+c+d+e=54を満たし、c及びdは同時に0とはならない。Siクラスレート化合物は、Siクラスレート化合物相、Si相、ランタノイド含有相を有し、化学式中のAがSrである場合は、Siクラスレート化合物中のSiクラスレート化合物相の割合αは0.35≦α<1、Si相の割合βは0<β<0.38、ランタノイド含有相の割合γは0<γ<0.65であり、化学式中のAがBaである場合は、割合αは0.75≦α<1、割合βは0<β<0.14、割合γは0<γ<0.25である。【選択図】図1 |
Author | NISHIKUBO HIDEO MORI TOMOHIKO FUJIMURA KOJI TADOKORO JUN KIKUCHI DAISUKE MIYOSHI KAZUTOMI |
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DocumentTitleAlternate | 熱電変換材料及びその製造方法、並びに、熱電変換素子、熱電変換モジュール、移動体 |
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Snippet | PROBLEM TO BE SOLVED: To provide a thermoelectric conversion material having high thermoelectric conversion characteristics even when used at high... |
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Title | THERMOELECTRIC CONVERSION MATERIAL AND METHOD OF PRODUCING THE SAME, AND THERMOELECTRIC CONVERSION ELEMENT, THERMOELECTRIC CONVERSION MODULE, AND MOVING BODY |
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